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Date: Wed, 20 Dec 2023 17:00:23 +0800
From: Baokun Li <libaokun1@...wei.com>
To: Jan Kara <jack@...e.cz>, <harshadshirwadkar@...il.com>
CC: <linux-ext4@...r.kernel.org>, <tytso@....edu>, <adilger.kernel@...ger.ca>,
	<ritesh.list@...il.com>, <linux-kernel@...r.kernel.org>,
	<yi.zhang@...wei.com>, <yangerkun@...wei.com>, <yukuai3@...wei.com>,
	<stable@...r.kernel.org>, Baokun Li <libaokun1@...wei.com>
Subject: Re: [PATCH 3/4] ext4: avoid bb_free and bb_fragments inconsistency in
 mb_free_blocks()

On 2023/12/18 23:14, Jan Kara wrote:
> On Mon 18-12-23 22:18:13, Baokun Li wrote:
>> After updating bb_free in mb_free_blocks, it is possible to return without
>> updating bb_fragments because the block being freed is found to have
>> already been freed, which leads to inconsistency between bb_free and
>> bb_fragments.
>>
>> Since the group may be unlocked in ext4_grp_locked_error(), this can lead
>> to problems such as dividing by zero when calculating the average fragment
>> length. Therefore, to ensure consistency, move the update of bb_free to
>> after the block double-free check.
>>
>> Fixes: eabe0444df90 ("ext4: speed-up releasing blocks on commit")
>> CC: stable@...r.kernel.org # 3.10
>> Signed-off-by: Baokun Li <libaokun1@...wei.com>
> I agree there's no point in updating the allocation info if the bitmap is
> corrupted. We will not try to allocate (or free) blocks in that group
> anymore. I'm just a bit unsure about the EXT4_FC_REPLAY state where we
> don't mark the bitmap as corrupted although some blocks were already marked
> as freed. So in this case the free space statistics tracking will go
> permanently wrong. I'm kind of wondering in which case does fast-commit
> free already freed blocks. Ted, any idea?
>
> 								Honza
>
Hello Harshad!

Seeing that earlier you added EXT4_FC_REPLAY related judgment to
mb_free_blocks() in commit 8016e29f4362 ("ext4: fast commit recovery path"),
when there is EXT4_FC_REPLAY, even when freeing blocks that have already
been freed, the block bitmap is not marked as corrupted, is there a known
scenario here?

I would be grateful if you could shed some light on this!


Thanks,
Baokun
>> ---
>>   fs/ext4/mballoc.c | 13 ++++++-------
>>   1 file changed, 6 insertions(+), 7 deletions(-)
>>
>> diff --git a/fs/ext4/mballoc.c b/fs/ext4/mballoc.c
>> index a95fa6e2b0f9..2fbee0f0f5c3 100644
>> --- a/fs/ext4/mballoc.c
>> +++ b/fs/ext4/mballoc.c
>> @@ -1892,11 +1892,6 @@ static void mb_free_blocks(struct inode *inode, struct ext4_buddy *e4b,
>>   	mb_check_buddy(e4b);
>>   	mb_free_blocks_double(inode, e4b, first, count);
>>   
>> -	this_cpu_inc(discard_pa_seq);
>> -	e4b->bd_info->bb_free += count;
>> -	if (first < e4b->bd_info->bb_first_free)
>> -		e4b->bd_info->bb_first_free = first;
>> -
>>   	/* access memory sequentially: check left neighbour,
>>   	 * clear range and then check right neighbour
>>   	 */
>> @@ -1922,9 +1917,14 @@ static void mb_free_blocks(struct inode *inode, struct ext4_buddy *e4b,
>>   				sb, e4b->bd_group,
>>   				EXT4_GROUP_INFO_BBITMAP_CORRUPT);
>>   		}
>> -		goto done;
>> +		return;
>>   	}
>>   
>> +	this_cpu_inc(discard_pa_seq);
>> +	e4b->bd_info->bb_free += count;
>> +	if (first < e4b->bd_info->bb_first_free)
>> +		e4b->bd_info->bb_first_free = first;
>> +
>>   	/* let's maintain fragments counter */
>>   	if (left_is_free && right_is_free)
>>   		e4b->bd_info->bb_fragments--;
>> @@ -1949,7 +1949,6 @@ static void mb_free_blocks(struct inode *inode, struct ext4_buddy *e4b,
>>   	if (first <= last)
>>   		mb_buddy_mark_free(e4b, first >> 1, last >> 1);
>>   
>> -done:
>>   	mb_set_largest_free_order(sb, e4b->bd_info);
>>   	mb_update_avg_fragment_size(sb, e4b->bd_info);
>>   	mb_check_buddy(e4b);
>> -- 
>> 2.31.1
>>


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